Area enclosed by a curve
The area between a curve y = f(x), the x-axis and the lines x = a and x = b is A = ∫ₐᵇ y dx (areas below the x-axis count as negative). The area between two curves is ∫ (upper − lower) dx.
Find the area between y = x², the x-axis, x = 0 and x = 3.
- Integrate.
Answer: The area is 9 square units.
Volume of a solid of revolution
When the area under y = f(x) from x = a to x = b is rotated through 360° about the x-axis, it makes a solid of volume:
The line y = x from x = 0 to x = 3 is rotated about the x-axis. Find the volume.
- Use the formula.
Answer: The volume is 9π ≈ 28.3 cubic units, the volume of a cone with r = h = 3: ⅓π×9×3.
Length of an arc
For a straight line y = x from 0 to 3, dy/dx = 1, so s = ∫√2 dx = 3√2 ≈ 4.24, which is the length given by Pythagoras.
Choose the upper limit b. Area = b³/3 and volume of revolution about the x-axis = πb⁵/5.
Key terms
- Solid of revolution
- A solid made by rotating a curve about an axis.
- Arc length
- The length along a curve.
- Definite integral
- Integral between two limits.
- Area between curves
- The integral of the upper minus the lower curve.
Summary
- Area = ∫ y dx between the limits.
- Volume of revolution = π∫ y² dx.
- Arc length = ∫ √(1 + (dy/dx)²) dx.
- Between two curves integrate (upper − lower).