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Rates and Variations

12 min read

Rates

A rate compares two quantities with different units, such as speed (km/h), price (TSh per kg) or a pay rate (TSh per hour). A rate is written "per" one unit of the second quantity.

Worked exampleA rate of work

A machine fills 360 bottles in 8 minutes. How many bottles in 30 minutes?

  1. Rate per minute.
  2. Multiply by 30 minutes.

Answer: 1 350 bottles.

Direct variation

Two quantities vary directly if one increases in the same ratio as the other: y = kx, where k is a constant. The graph is a straight line through the origin. Example: the cost of x kg of rice.

Doubling x doubles y. The line passes through the origin.

Inverse variation

Two quantities vary inversely if one increases as the other decreases so that their product is constant: y = k/x. The graph is a curve (a hyperbola). Example: the time to do a job and the number of workers.

Doubling x halves y.
TypeEquationFinding kGraph
Directy = kxk = y ÷ xStraight line through the origin
Inversey = k/xk = xyHyperbola
Jointz = kxyk = z ÷ xy
Partialy = a + bxTwo constantsLine not through the origin
Worked exampleInverse variation

6 workers build a wall in 10 days. How long would 15 workers take?

  1. Days vary inversely with workers: workers × days is constant.
  2. Divide by 15.

Answer: 4 days.

Try itDirect and inverse variation

Choose k and x. See how y changes in each kind of variation.

Check yourself If y varies directly as x and y = 12 when x = 4, then k =
Check yourself If 4 pipes fill a tank in 6 hours, 8 pipes fill it in...
Check yourself The graph of y = k/x is a...

Key terms

Rate
A comparison of two quantities with different units.
Direct variation
y = kx.
Inverse variation
y = k/x.
Constant of variation
The fixed number k.

Summary

  • A rate compares quantities with different units.
  • Direct variation: y = kx, a line through the origin.
  • Inverse variation: y = k/x, so xy is constant.
  • Find k from one pair of values, then use it.