Saturated solutions and the solubility product
In a saturated solution of a sparingly soluble salt, the solid is in dynamic equilibrium with its ions: AgCl(s) ⇌ Ag⁺(aq) + Cl⁻(aq). The equilibrium constant, which leaves out the solid, is the solubility product K_sp.
| Salt | Dissolving | K_sp expression | K_sp at 25 °C |
|---|---|---|---|
| Silver chloride, AgCl | AgCl ⇌ Ag⁺ + Cl⁻ | [Ag⁺][Cl⁻] | 1.8 × 10⁻¹⁰ mol²/dm⁶ |
| Barium sulphate, BaSO₄ | BaSO₄ ⇌ Ba²⁺ + SO₄²⁻ | [Ba²⁺][SO₄²⁻] | 1.1 × 10⁻¹⁰ |
| Calcium hydroxide, Ca(OH)₂ | Ca(OH)₂ ⇌ Ca²⁺ + 2OH⁻ | [Ca²⁺][OH⁻]² | 5.5 × 10⁻⁶ |
| Lead(II) iodide, PbI₂ | PbI₂ ⇌ Pb²⁺ + 2I⁻ | [Pb²⁺][I⁻]² | 7.1 × 10⁻⁹ |
The K_sp of silver chloride is 1.8 × 10⁻¹⁰. Find the solubility in mol/dm³.
- If s mol/dm³ dissolves, [Ag⁺] = [Cl⁻] = s.
- K_sp = s².
Answer: The solubility of AgCl is about 1.3 × 10⁻⁵ mol/dm³.
Choose the type of salt (1 = AB, such as AgCl; 2 = AB₂, such as PbI₂) and its K_sp as a power of ten. Find the solubility s.
Precipitation and the common ion effect
A precipitate forms if the ionic product (the same expression as K_sp using the concentrations at that moment) is greater than K_sp. No precipitate forms if it is less. The common ion effect: adding a soluble salt that shares an ion with a sparingly soluble salt reduces its solubility. Silver chloride is much less soluble in sodium chloride solution than in pure water.
Applications
| Application | Idea |
|---|---|
| Water softening | Adding sodium carbonate precipitates Ca²⁺ as insoluble CaCO₃ |
| Barium meal in X-rays | BaSO₄ is so insoluble that the toxic Ba²⁺ is not absorbed |
| Testing for chloride ions | Silver nitrate forms insoluble AgCl |
| Tooth enamel | Hydroxyapatite dissolves in acid, which is why sugar and acid cause decay; fluoride makes it less soluble |
| Removing heavy metals from waste water | Precipitation as hydroxides or sulphides |
Key terms
- Solubility product
- K_sp, the equilibrium constant for a sparingly soluble salt dissolving.
- Ionic product
- The product of the ion concentrations at a given moment.
- Common ion effect
- The reduction in solubility of a salt caused by a common ion from another source.
- Sparingly soluble
- Dissolving only very slightly.
Summary
- K_sp is the product of the ion concentrations in a saturated solution.
- AB: s = √K_sp; AB₂: s = (K_sp ÷ 4)^(1/3).
- A precipitate forms when the ionic product exceeds K_sp.
- A common ion decreases solubility.